JEE Mains 2026 - 21/1/2026-S1 | Wave Speed on Different Strings | Complete Solution скачать в хорошем качестве

JEE Mains 2026 - 21/1/2026-S1 | Wave Speed on Different Strings | Complete Solution

Complete solution from JEE Mains 2026 (21st January 2026 - Shift 1) Physics Paper. 📌 Topic: Waves | Wave Speed on String ❓ Question: Two strings (A, B) having linear densities μₐ = 2×10⁻⁴ kg/m and μᵦ = 4×10⁻⁴ kg/m and lengths Lₐ = 2.5 m and Lᵦ = 1.5 m respectively are tied to two rigid supports C and D, respectively creating a tension of 500 N in the wire. Two identical pulses, sent from C and D ends, take time t₁ and t₂, respectively, to reach the joint. Find the ratio t₁/t₂. Options: 1.90 1.67 1.18 1.08 ✅ Solution Includes: Wave speed formula on string: v = √(T/μ) Speed calculation for both strings Time calculation: t = L/v Ratio determination: t₁/t₂ Step-by-step numerical solution Correct answer with complete explanation 🎯 Perfect for: JEE Mains 2026 aspirants Waves chapter revision String wave problems Wave speed calculations 📚 Part of my complete JEE Mains 2026 solution series with detailed explanations! 🔔 Subscribe for daily JEE Mains physics solutions 👍 Like if this helped you understand wave motion 💬 Comment your approach to this problem #JEEMains2026 #Waves #WaveMotion