JEE Main 2026 Physics Solution: 24 Jan Shift 2 | Nucleus Binding Energy & Stability скачать в хорошем качестве

JEE Main 2026 Physics Solution: 24 Jan Shift 2 | Nucleus Binding Energy & Stability

Detailed step-by-step solution for JEE Mains 2026 (24 January, Shift 2) Physics question on the Nucleus, focusing on Binding Energy and Stability. Question: Q.30 The binding energy for the following nuclear reactions are expressed in MeV. (3, 2)He + (1, 0)n → (4, 2)He + 20 MeV (4, 2)He + (1, 0)n → (5, 2)He - 0.9 MeV If X3, X4, X5 denote the stability of (3, 2)He, (4, 2)He and (5, 2)He, respectively, then the correct order is : In this video, we analyze the thermodynamics of these nuclear reactions. We break down how the release or absorption of energy dictates an increase or decrease in binding energy, and how to combine equations to find the exact stability relationship between all three isotopes without skipping any logical steps. Timestamps: 0:00 - Intro & Question Reading 0:48 - Analyzing Reaction 1 (Stability of He-3 vs He-4) 1:18 - Analyzing Reaction 2 (Stability of He-4 vs He-5) 1:56 - Adding Equations to Compare He-3 and He-5 2:46 - Final Stability Order & Answer Don't forget to like and subscribe to Physics Unlocked ⚛🔓 for more in-depth JEE Physics solutions!