Spring + Pulley = SHM Shock 😱 | Period = 2π√(4m/k) скачать в хорошем качестве

Spring + Pulley = SHM Shock 😱 | Period = 2π√(4m/k)

In this video, PK Sir explains a tricky SHM (Simple Harmonic Motion) problem involving a spring–pulley system. This question is very important for Class 11 & Class 12 Physics and is frequently asked in board exams and competitive exams. You will clearly understand: ✔ How tension changes in a spring–pulley arrangement ✔ Why the effective spring constant becomes different ✔ Step-by-step derivation of the time period ✔ Final result: T = 2π √(4m / k) 💡 Most students make mistakes in this type of question due to wrong force analysis. This video will help you avoid common errors and score full marks. 👉 Watch till the end for the shortcut method and exam tips. ⸻ 🎯 Useful For • Class 11 Physics • Class 12 Physics • CBSE / State Board • JEE / NEET Foundation ⸻ 🔍 Keywords (SEO) Spring pulley SHM, SHM physics, effective spring constant, time period of oscillation, Class 11 Physics SHM, Class 12 Physics mechanics, PK Sir Physics ⸻ 📌 Hashtags #SHM #SpringPulley #PhysicsNumericals #Class11Physics #Class12Physics #Mechanics #PKSir #physics #cbse #education #neetexam #neetpreparation #jeemains #mechanic #neet #physicsfun #workenergy