Projectile : 😇 Fastest Revision😇 for droppers NEET, JEE + 100 Oral Questions+ How to make new MCQs скачать в хорошем качестве

Projectile : 😇 Fastest Revision😇 for droppers NEET, JEE + 100 Oral Questions+ How to make new MCQs

The video provides a rapid revision of projectile motion, focusing on key concepts and formulas relevant for NEET and JEE exams. The instructor, DebKunj CLASSES, explains various scenarios of projectile motion, including objects dropped from a height, projected horizontally, and projected at an angle from both a height and ground level. Here are the key takeaways from the video: Time of Flight from a Height (1:06): The time taken for an object dropped or projected horizontally from a height `h` to reach the ground is given by `T = sqrt(2h/g)`. The instructor demonstrates how changes in `h` or `g` affect the time of flight, including scenarios where `g` varies with altitude. Horizontal Velocity and Momentum (6:31): In the absence of air resistance, the horizontal component of velocity remains constant throughout the projectile's flight. Consequently, the horizontal momentum and horizontal kinetic energy also remain constant. Vertical Velocity and Momentum (7:19): The vertical velocity changes due to gravity. When an object is dropped, its initial vertical velocity is zero, and it increases with time (`v = gt`). The vertical momentum also increases accordingly (`p = mgt`). Velocity and Angle at Impact (7:42, 12:17): The video explains how to calculate the resultant velocity and the angle it makes with the horizontal or vertical at any point, including the moment of impact, using vector addition and trigonometry. Maximum Height (Hmax) (28:15): The maximum vertical height attained by a projectile launched from the ground at an angle `theta` with initial velocity `u` is `Hmax = (u^2 * sin^2(theta)) / (2g)`. This is the distance an object can go vertically upwards given its initial velocity. Range (R) (29:32): The horizontal distance covered by a projectile launched from the ground at an angle `theta` with initial velocity `u` is `R = (u^2 * sin(2*theta)) / g`. The maximum range occurs when `theta = 45` degrees, given by `Rmax = u^2 / g`. The video also highlights the relationship between maximum range and maximum height (`Rmax = 2 * H_max`). Time of Flight from Ground (23:12): For a projectile launched from the ground and landing on the same level, the time of flight is `T = (2u * sin(theta)) / g`. Equation of Trajectory (41:17): The path of a projectile can be described by the equation `y = xtan(theta) - (gx^2) / (2u^2 * cos^2(theta))`. A simplified form `y = x*tan(theta) * (1 - x/R)` is also discussed, useful for quickly determining the range. Kinetic Energy at Highest Point (45:32): At the highest point of a projectile's path, the vertical velocity is zero, and only the horizontal velocity (`ucos(theta)`) remains. The kinetic energy at this point is `1/2 * m * (ucos(theta))^2`. Angular Momentum (53:56): The video introduces angular momentum `L` as the product of momentum `p` and the perpendicular distance `r` from the point about which angular momentum is calculated (`L = p * r_perpendicular`). It explains how to calculate angular momentum at different points of the projectile's trajectory relative to a reference point.