JEE Mains 2026 - 21/1/2026-S1 | EMI - Moving Conductor in Magnetic Field скачать в хорошем качестве

JEE Mains 2026 - 21/1/2026-S1 | EMI - Moving Conductor in Magnetic Field

Complete solution to Question 33 from JEE Mains 2026 (21st January 2026 - Shift 1) Physics Paper. 📌 Topic: Electromagnetic Induction | Motional EMF ❓ Question: A 1 m long metal rod AB completes the circuit as shown in figure. The area of circuit is perpendicular to the magnetic field of 0.10 T. If the resistance of the total circuit is 2 Ω then the force needed to move the rod towards right with constant speed (v) of 1.5 m/s is _______ N. Options: 5.7×10⁻³ 7.5×10⁻³ 7.5×10⁻² 5.7×10⁻² ✅ Solution Includes: Motional EMF formula: ε = Bvl Induced current calculation (I = ε/R) Magnetic force on current-carrying conductor: F = BIl Force balance for constant velocity Step-by-step numerical solution Correct answer with complete derivation 🎯 Perfect for: JEE Mains 2026 aspirants Electromagnetic Induction revision Motional EMF problems Force and EMI applications 📚 Part of my complete JEE Mains 2026 solution series with detailed explanations! 🔔 Subscribe for daily JEE Mains physics solutions 👍 Like if this helped you understand motional EMF 💬 Comment your doubts or alternate methods #JEEMains2026 #ElectromagneticInduction #MotionalEMF