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Here's my solution to the LeetCode Problem 1657: Determine If Two Strings Are Close, implemented in C# using Dictionaries and Sorting. 🚀 💡 Problem Overview: The challenge is to check if two strings word1 and word2 are close. For two strings to be close: They must have the same length. They must have the same set of unique characters. The frequency of unique characters in both strings must be the same but can be rearranged (order doesn't matter). This solution uses dictionaries to track frequency counts and then validates the conditions with sorting and comparisons. ✅ What You'll Learn in This Video: How to effectively use Dictionaries to count characters and their frequencies in a string. Validating conditions efficiently with Sorting and a logical flow. A clean and step-by-step implementation in C#, optimized for readability and correctness. 🔔 Code Highlights: Time Complexity: O(n log n). Calculating character frequencies takes O(n), but sorting the frequency lists takes O(n log n), where n is the length of the strings. Space Complexity: O(u), where u is the number of unique characters, as both dictionaries require space proportional to the number of distinct characters in the strings. Core Insight: The solution uses dictionaries to efficiently count character occurrences, and sorting ensures that the frequencies are comparable regardless of their original arrangement. Logical checks for length and unique character sets simplify the validation process. 💡 This problem is a great example of combining substring analysis, dictionary usage, and sorting techniques. It's perfect for advancing your skills in solving string manipulation and frequency-based challenges often seen in coding interviews. 🎥 If you enjoyed this detailed explanation and walkthrough, don’t forget to Like, Subscribe, and Share for more LeetCode problem breakdowns, coding strategies, and algorithm tutorials! ✨ #LeetCode #CloseStrings #Dictionary #StringManipulation #CSharp #FrequencyCount #Sorting #ProblemSolving #CodingInterview #Algorithms