One Pass Greedy Solution | Minimum Deletions to Make String Balanced | LeetCode 1653 скачать в хорошем качестве

One Pass Greedy Solution | Minimum Deletions to Make String Balanced | LeetCode 1653

In this video, we solve LeetCode 1653. Minimum Deletions to Make String Balanced using a simple counting observation. The key idea is to understand what a balanced string means: • All 'a' characters must come before any 'b' So at every index, we decide: • Delete 'b' characters seen on the left, or • Delete remaining 'a' characters on the right Instead of trying all deletions, we maintain: 1️⃣ Count of remaining 'a' characters 2️⃣ Count of 'b' characters seen so far The minimum deletions at any point becomes: count_b + count_a This leads to a clean single-pass O(n) solution with constant space. This problem is part of today’s LeetCode Daily Problem of the Day (POTD). 🔹 What you’ll learn: • How to convert string problems into counting problems • Why tracking left and right counts works • How to minimize deletions greedily • O(n) time and O(1) space solution 🔹 Topics: • Strings • Greedy • Prefix Counting Clear problem explanation, intuition-first walkthrough, and clean Java implementation. Problem link - https://leetcode.com/problems/minimum... Java Code - https://pastebin.com/79pR2GtJ Python Code - https://pastebin.com/jRbq9cTH Time complexity - O(N) Space Complexity - O(1) Page Marker Extension - https://chromewebstore.google.com/det... Video Chapters - 00:00 - Problem Statement 05:11 - Approach 19:32 - Code 21:46 - Time and Space Complexity Leetcode daily playlist -    • LeetCode Daily Problems   LeetCode Easy POTD playlist -    • LeetCode Easy   LeetCode Medium POTD playlist -    • LeetCode Medium   LeetCode Hard POTD playlist -    • LeetCode Hard   If you want to practice daily and improve your problem-solving skills, this is the place to follow along. #leetcode #dsa #strings #prefixsum #greedy #leetcodeproblemoftheday #algorithm #java #python #code #leetcodechallenge #codinginterview #problemsolving