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We will use L'Hospital's Rule for the limit of x^sqrt(x) as x goes to 0+. Even though we will get a 0^0 when we plug in 0 into x^sqrt(x), 0^0 IS an indeterminate form so we must do more work in order to determine the limit. Here's an example of the limit with the indeterminate form 0^0 but we do not get 1. 👉 • a 0^0 limit that approaches e This is how to spell L'Hospital's rule: 👉 • how to spell L’Hosptisl’s Rule? Get a derivative t-shirt: 👉 https://bit.ly/derivativetshirt Use "WELCOME10" for 10% off Subscribe for more precalculus & calculus tutorials 👉 @bprpcalculusbasics ------------------- If you find this channel helpful and want to support it, then you can join the channel membership and have your name in the video descriptions: 👉https://bit.ly/joinjustcalculus buy a math shirt or a hoodie (10% off with the code "WELCOME10"): 👉 https://bit.ly/bprp_merch I use these markers 👉 https://amzn.to/3skwj1E ------------------- 😊 Thanks to all channel members 😊 Sandglass Dªrksun Seth Morris Andrea Mele --------------------------------------------------------- "Just Calculus" is dedicated to helping students who are taking precalculus, AP calculus, GCSE, A-Level, year 12 maths, college calculus, or high school calculus. Topics include functions, limits, indeterminate forms, derivatives, and their applications, integration techniques and their applications, separable differential equations, sequences, series convergence test, power series a lot more. Feel free to leave calculus questions in the comment section and subscribe for future videos 👉 https://bit.ly/just_calc --------------------------------------------------------- Best wishes to you, #justcalculus