The time required for 10% completion of a first order reaction at 298 K is equal to that required скачать в хорошем качестве

The time required for 10% completion of a first order reaction at 298 K is equal to that required

Unlock the secrets of Chemical Kinetics with detailed NCERT-based solutions for Class 12 Chemistry. In this video, Chemistry expert OSB breaks down key concepts, solved examples, and important tricks for CBSE Board, NEET, and JEE aspirants. Perfect for last-minute revision and conceptual clarity! The time required for 10% completion of a first order reaction at 298 K is equal to that required for its 25% completion at 308 K. If the value of A is 4 \times 10^{10} \, \text{s}^{-1}, calculate k at 318 K and E_a. 📘 Topics Covered: • Rate of Reaction • Integrated Rate Law • First & Zero Order Reactions • Units of Rate Constant • Arrhenius Equation • Graphical Tricks & Mistake Traps 🔍 Ideal for Class 12 CBSE students, NEET/JEE aspirants, and anyone aiming for high scores with smart strategies. 🎯 Explained by: OSB – CBSE Chemistry Expert Subscribe for more NCERT solutions, exam tips, and powerful shortcuts! ⸻ 20 Hashtags: #ChemicalKinetics, #Class12Chemistry, #NCERTSolutions, #CBSEChemistry, #NEET2025, #JEE2025, #ChemistryWithOSB, #CBSEBoard2025, #ScienceWithOSB, #RateOfReaction, #ArrheniusEquation, #ChemistryTricks, #IntegratedRateLaw, #CBSETipsAndTricks, #ZeroOrderReaction, #FirstOrderReaction, #JEEChemistry, #NEETChemistry, #ChemistryRevision, #NcertClass12