Leetcode 1653 скачать в хорошем качестве

Leetcode 1653

In this video, we solve the “Minimum Deletions to Make String Balanced” problem using an efficient O(n) greedy approach. We’ll walk through: The corrected Python implementation The intuition behind the algorithm A clear explanation using counters instead of brute force Time and space complexity analysis Problem Overview A string is considered balanced if all 'a' characters appear before all 'b' characters. Goal: Find the minimum number of deletions required to make the string balanced. Key Idea At every position in the string: Count how many 'b' characters are on the left Count how many 'a' characters are on the right The sum of these tells us how many deletions are needed at that split point We compute this efficiently in one pass. Example Walkthrough Input: s = "aababbab" Total 'a' count = 4 Track deletions needed at each index Minimum deletions required = 2 Complexity Analysis Metric Complexity Time O(n) Space O(1) 🔥 Why This Approach? No extra arrays No nested loops Works perfectly for large inputs Ideal for interviews and competitive programming #LeetCode #StringManipulation #PrefixSum #SuffixSum #DynamicProgramming #AlgorithmDesign #ProblemSolving #LeetCode1653 #Cplusplus #DSA #techinterview #leetcodepotd #leetcodecoding #leetcodechallenge