“Given Rₓₓ(τ)=(25τ²+36)/(625τ²+4) | Find Mean, Mean-Square & Variance | Complete Derivation” скачать в хорошем качестве

“Given Rₓₓ(τ)=(25τ²+36)/(625τ²+4) | Find Mean, Mean-Square & Variance | Complete Derivation”

📘 In this video, we solve an important Random Process problem: 👉 A stationary random process has an autocorrelation function: Rₓₓ(τ) = (25τ² + 36) / (625τ² + 4) We will find the mean value, mean-square value, and variance of the process X(t) — step-by-step, using the properties of the autocorrelation function. ✅ What You’ll Learn in This Video: Relationship between autocorrelation and mean How to find: 🔹 Mean² = Rₓₓ(∞) 🔹 Mean-square value = Rₓₓ(0) 🔹 Variance = Rₓₓ(0) - Rₓₓ(∞) Simplified derivation with clear explanation Final numeric results and their interpretation 💡 Key Concepts Covered: Stationary Random Process Autocorrelation Function (ACF) Mean, Mean-Square, and Variance Relations Power and Randomness Interpretation 🎯 Perfect For: B.Tech / M.Tech ECE, CSE, EEE students GATE / ESE / UGC NET aspirants Learners of Probability, Random Processes, and Signal Analysis 🔥 Watch till the end for a clear understanding of how to extract all statistical parameters directly from Rₓₓ(τ)! 👍 Like, Share & Subscribe for more step-by-step Random Process derivations and exam-focused explanations!