Thermodynamics lec 13 Part 2|Bond Energy&Heat of Neutralization|Thermochemistry Mastery скачать в хорошем качестве

Thermodynamics lec 13 Part 2|Bond Energy&Heat of Neutralization|Thermochemistry Mastery

Thermodynamics Lec 13 Part 2 | Bond Energy & Heat of Neutralization | Thermochemistry Mastery | KKSir Namaste Dear Students! 🙏 Welcome to the most detailed and conceptually rich session of our Thermodynamics series. In Lecture 13 (Part 2), Krishna Kumar Sah (ChembyKKSir) completes the puzzle of Thermochemistry. This lecture is specifically designed to take you from the basic NCERT level to the complex problem-solving patterns of JEE Advanced and NEET. Why this Lecture is the "Heart" of Physical Chemistry: Thermochemistry isn't just one chapter; it's the energy foundation for the entire Chemistry syllabus. The concepts of Bond Energy and Enthalpy taught today are the "Master Keys" to: Chemical Bonding: Understanding why some bonds are stronger than others and how Bond Enthalpy relates to Bond Order and Bond Length. GOC & Hydrocarbons: Calculating the stability of intermediates, Heat of Hydrogenation (HoH), and the Resonance Energy of aromatic compounds like Benzene. Chemical Equilibrium: Predicting how a reaction shifts with temperature changes using the Van’t Hoff equation (ΔH is the hero here!). Electrochemistry: Connecting the Enthalpy of a reaction to the Gibbs Free Energy (ΔG) and Cell Potential (Ecell). Chemical Kinetics: Understanding the Activation Energy (Ea) and the transition state through Energy Profile Diagrams. Atomic Structure: Linking Bond Energy with Electron Gain Enthalpy and Ionization Energy. 🔥 What We Master in This Masterclass: ✅ The Bond Energy (B.E.) Revolution: Learn why Bond Energy is the only formula where we use Σ B.E. (Reactants) - Σ B.E. (Products). We decode the logic behind breaking bonds (Endothermic) and forming bonds (Exothermic) so you never make a sign convention mistake again! ✅ Heat of Neutralization (Advanced Cases): We go beyond the standard -57.1 kJ/eq. We discuss why the heat is lower when Weak Acids (like CH3COOH) or Weak Bases (like NH4OH) are involved. We explore the "Heat of Ionization" and the rare case of HF where the heat is actually higher! ✅ The "Big 3" Enthalpy Comparison: A crystal-clear comparison of how to calculate the Enthalpy of Reaction (ΔHrxn) using three different data sets: Case 1: Using Enthalpy of Formation (ΔHf) → P - R Case 2: Using Enthalpy of Combustion (ΔHc) → R - P Case 3: Using Bond Enthalpy (B.E.) → R - P ✅ JEE Advanced Numerical Solving: We solve high-level problems involving multiple bond types, resonance energy corrections, and polyatomic molecules. ✅ Meaningful Guidance & Homework: KKSir explains how to categorize the remaining "Heats of Reaction" (Atomization, Phase Transition, Solution, and Hydration). These are assigned as homework to ensure you become a self-reliant problem solver! 🚀 Connect with ChembyKKSir (Original Links for Max Subscribers): 🔹 YouTube:    / @chembykksir   🔹 Instagram:   / chembykksir   🔹 WhatsApp Channel: https://whatsapp.com/channel/0029Vb6F... 🔹 Telegram: https://t.me/chembykksir 🔹 Facebook: https://www.facebook.com/share/1ACSwY... 🔹 LinkedIn:   / krishna-kumar-sah-13708661   #Thermodynamics #Thermochemistry #BondEnergy #HeatOfNeutralization #KKSir #JEEAdvanced #NEET2026 #PhysicalChemistry #ChemistryByKKSir #BondEnthalpy #HeatOfFormation #HessLaw #ChembyKKSir #JEE2026 #Class11Chemistry #ReactionEnthalpy Thermodynamics Lec 13 Part 2, Bond Energy vs Bond Dissociation Enthalpy, Heat of Neutralization Full Detail, Enthalpy of Reaction using Bond Energy, Heat of Formation vs Combustion, JEE Advanced Thermochemistry, NEET Bond Energy Numericals, Krishna Kumar Sah, ChembyKKSir, Resonance Energy Calculation, Bond Energy formula Reactant minus Product, Thermodynamics for JEE Main, Thermochemistry for NEET, KKSir Chemistry Lectures. "Namaste Students! In today's lecture, we unlocked the R - P logic for Bond Energy. Remember, 'Bonds Broken' is always a 'Cost' (Energy in), and 'Bonds Formed' is always a 'Profit' (Energy out)! 🧪 Challenge Question: If the Bond Energy of C-C is 348 kJ/mol and C=C is 614 kJ/mol, why isn't the double bond exactly double the single bond? Comment your logic below! 👇"