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In this example problem, we find the equation of a tangent line to a curve at a given value by finding the derivative. The derivative represents the slope of tangent lines to a curve, so the slope of our line can be found by evaluating the derivative at the given value for our variable. We evaluate our original function at the given value of our variable to create a point on our line. With the slope of our line and a point on our line, we use the slope-intercept form of a line and fill in our information, solve for our y-intercept b and create the equation of our tangent line to the curve at the given value. This video contains examples that are from Business Calculus, 1st ed, by Calaway, Hoffman, Lippman. from the Open Course Library, remixed from Dale Hoffman's Contemporary Calculus text. It was extended by David Lippman to add several additional topics. The text is licensed under the Creative Commons Attribution license. http://creativecommons.org/licenses/b...