Aldehyde and Ketone "Crossed Aldol Condensation" reaction by R Kumar скачать в хорошем качестве

Aldehyde and Ketone "Crossed Aldol Condensation" reaction by R Kumar

Aldehyde and Ketone | Crossed Aldol Condensation reaction | by R Kumar @apex-tutorial #neetstrategy #chemistry #jeebatch #medicalentrance #jeeproblems #jee #jeemains #chemistrychamps #jeeadvanced Here's a breakdown of the key concepts: Process and Products : The reaction initially forms beta-hydroxy aldehyde or beta-hydroxy ketone. To achieve a more stable product, these then eliminate water, converting into alpha-beta unsaturated aldehyde or alpha-beta unsaturated ketone. A key characteristic of crossed aldol condensation is the formation of four possible products . Mechanism with Examples : The video uses the example of ethanal (A) and propanal (B) reacting in the presence of dilute alkali to illustrate the four possible products . The mechanism involves the loss of an acidic alpha-hydrogen to form an enolate. This enolate then acts as a nucleophile, combining with another molecule through a nucleophilic addition reaction. The four products arise from: 1. Enolate from A reacting with B. 2. Enolate from B reacting with A. 3. Enolate from A reacting with A (self-condensation). 4. Enolate from B reacting with B (self-condensation). Distinction from Aldol Condensation: Crossed Aldol Condensation specifically involves two different molecules (aldehyde or ketone). When the reaction involves two same molecules, it is simply called Aldol Condensation. Both reactions require the presence of alpha-hydrogen atoms.